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Q. 68

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Physics for Scientists and Engineers: A Strategic Approach with Modern Physics
Found in: Page 203

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Short Answer

The father of Example 8.2 stands at the summit of a conical hill as he spins his 20 kg child around on a 5.0 kg cart with a 2.0-m-long rope. The sides of the hill are inclined at 20o­. He again keeps the rope parallel to the ground, and friction is negligible. What rope tension will allow the cart to spin with the same 14 rpm it had in the example?

The tension on the rope is 185.4 N.

See the step by step solution

Step by Step Solution

Step1: Given information

Total mass of cart and child, m=20+5=25 kg
Radius of the rope, r=2 mAngle of the hill, θ=20o Angular speed, N=14 rpm

Step2: Explanation

First draw the Free body diagram from the given information

Angular velocity is calculated by

Substitute the values, we get

From the figure we can equate the horizontal forces to calculate tension

substitute the values, we get

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