Does the loop of wire in FIGURE have a clockwise current, a counterclockwise current, or no current under the following circumstances? Explain.
a. The magnetic field points out of the page and is increasing.
b. The magnetic field points out of the page and is constant.
c. The magnetic field points out of the page and is decreasing
(a) When the field of force is rising and points out of the page, the wire loop is clockwise.
(b) When the Flux points out of the page and is constant, the wire loop has no current.
(c) When the Flux points out of the page and is decreasing, the wire loop is counterclockwise.
A field is produced along the length of a wire loop by a current flowing through it. Curling the finger of the right hand within the direction of the current through the loop, the thumb then points within the direction of the field of force, reveals the direction of the sphere inside the loop.
(a) The induced field is into the page, and the induced current is clockwise according to the right-hand rule.
(b) The current must be induced by a changing magnetic flux. As a result, there's no current
(c) Because the induced magnetic flux is off the page, the wire loop should be turned counterclockwise.
56. II Your camping buddy has an idea for a light to go inside your CALC tent. He happens to have a powerful (and heavy!) horseshoe magnet that he bought at a surplus store. This magnet creates a T field between two pole tips apart. His idea is to build the hand-cranked generator shown in FIGURE P30.56. He thinks you can make enough current to fully light a lightbulb rated at . That's not super bright, but it should be plenty of light for routine activities in the tent.
a. Find an expression for the induced current as a function of time if you turn the crank at frequency f Assume that the semicircle is at its highest point at .
b. With what frequency will you have to turn the crank tor the maximum current to fully light the bulb? Is this feasible?
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