Q.7

Expert-verified
Found in: Page 384

### Physics for Scientists and Engineers: A Strategic Approach with Modern Physics

Book edition 4th
Author(s) Randall D. Knight
Pages 1240 pages
ISBN 9780133942651

# A 3.0-cm-diameter tube is held upright and filled to the top with mercury. The mercury pressure at the bottom of the tube— the pressure in excess of atmospheric pressure—is 50 kPa. How tall is the tube?

The height of tube is 0.38 m

See the step by step solution

## Given information

Diameter of tube =3.0-cm = 0.03 m

It is filled to the top with mercury.

The mercury pressure at the bottom of the tube—the pressure in excess of atmospheric pressure—is 50 kPa.

## Explanation

The pressure exerted by the mercury is given as

P = hρg ...............................(1)

p = 50 x 103 Pa

h = depth of liquid

ρ= density of liquid

g = gravitational acceleration

Calculate hρg , consider g = 9.8 m/s2 and density of mercury is 13.6 x103kg/m3

hρg= 50 x 103 = h x 13.6 x103kg/m3 x 9.8 m/s2

Height of tube = 0.38 m.