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Q.7

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Physics for Scientists and Engineers: A Strategic Approach with Modern Physics
Found in: Page 384

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Short Answer

A 3.0-cm-diameter tube is held upright and filled to the top with mercury. The mercury pressure at the bottom of the tube— the pressure in excess of atmospheric pressure—is 50 kPa. How tall is the tube?

The height of tube is 0.38 m

See the step by step solution

Step by Step Solution

Given information

Diameter of tube =3.0-cm = 0.03 m

so radius is 0.015m

It is filled to the top with mercury.

The mercury pressure at the bottom of the tube—the pressure in excess of atmospheric pressure—is 50 kPa.

Explanation

The pressure exerted by the mercury is given as

P = hρg ...............................(1)

p = 50 x 103 Pa

h = depth of liquid

ρ= density of liquid

g = gravitational acceleration

Calculate hρg , consider g = 9.8 m/s2 and density of mercury is 13.6 x103kg/m3

hρg= 50 x 103 = h x 13.6 x103kg/m3 x 9.8 m/s2

Height of tube = 0.38 m.

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