A single force with x-component Fx acts on a 2.0 kg object as it moves along the x-axis. A graph of Fx versus t is shown in FIGURE . Draw an acceleration graph (ax versus t) for this object.
According to Newton's Second Law of Motion, the force acting on the object is directly proportional to the acceleration of the object. The force is equal to the product of mass and acceleration of the object.
The mass of the object is m = 2 kg
The force is acting along the X-axis.
Force vs time graph is given.
The formula to calculate the force is given by F = ma.
Therefore, the formula to calculate the acceleration of the object is given by
Substitute different values of forces and 2 kg for m to calculate the respective accelerations.
As calculated above, plug the values of time and acceleration in the excel sheet and draw the graph obtained.
Problems 35 through 40 show a free-body diagram. For each:
a. Identify the direction of the acceleration vector and show it as a vector next to your diagram. Or, if appropriate, write b. If possible, identify the direction of the velocity vector and show it as a labeled vector.
c. Write a short description of a real object for which this is the
correct free-body diagram. Use Examples 5.4, 5.5, and 5.6 as
models of what a description should be like.
The leaf hopper, champion jumper of the insect world, can
jump straight up at 4 m/s2. The jump itself lasts a mere 1 ms before the insect is clear of the ground.
a. Draw a free-body diagram of this mighty leaper while the
jump is taking place.
b. While the jump is taking place, is the force of the ground on
the leaf hopper greater than, less than, or equal to the force of
gravity on the leaf hopper? Explain.
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