Q. 17

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Found in: Page 791

### Physics for Scientists and Engineers: A Strategic Approach with Modern Physics

Book edition 4th
Author(s) Randall D. Knight
Pages 1240 pages
ISBN 9780133942651

# The battery in FIGURE is short-circuited by an ideal ammeter having zero resistance. a. What is the battery’s internal resistance? b. How much power is dissipated inside the battery?

(a) The battery's internal resistance is.

(b) The power dissipated inside the battery is.

See the step by step solution

## Part (a) step 1: Given information

We have given that the battery is short-circuited by an ideal ammeter having zero resistance.

We need to find that the battery's internal resistance.

## Part (a) step 2: Simplify

The real batteries have an internal resistance due to their components while the ideal batteries have zero internal resistance. When an ideal wire with zero resistance is connected to the two terminals of the battery, it will make a short circuit where the current is maximum. For a battery that is connected to a circuit, the current that flows through the circuit is given as

In a short circuit, the resistance . So, equation (1) could be rearranged for to be in the form

The ammeter reads current .Plug the value of and into equation (2) to get

## Part (b) step 1: Given information

We have given that the battery is short-circuited by an ideal ammeter having zero resistance.

We need to find that how much power is dissipated inside the battery.

## Part (b) step 2: Simplify

The energy is dissipated when the current flows through a resistor. The rate of the dissipated energy is the power. It is given as

Putting the values for and into equation (3) to get