The 10 Ω resistor in FIGURE EX28.29 is dissipating of power. How much power are the other two resistors dissipating?
The power of other two resistors are and .
We need to find that How much power are the other two resistors dissipating?
of the power is dissipated by resistor. So, calculating the current through the resistance . The energy is dissipated when the current flows through a resistor. The rate of the dissipated energy is the power. This rate where the energy is transferred from the current to the resistor is
Use equation (1) and solve it for the current and plug the value for and to get by
The current is the same for the resistors, and as the two resistors and are in series, the current and is same.
Putting the values for the current and into equation (1) to get the dissipated power by resistance by
The potential difference in the upper branch could be calculated by
The potential difference across the resistors is the same in parallel connection. So, the voltage across the below resistor is . So, this value to get the power through the resistor by
A battery is a voltage source, always providing the same potential difference regardless of the current. It is possible to make a current source that always provides the same current regardless of the potential difference. The circuit in FIGURE P28.56 is called a current divider. It sends a fraction of the source current to the load. Find an expression for in terms of and You can assume that the load’s resistance is much less than
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