Log In Start studying!
Answers without the blur. Sign up and see all textbooks for free! Illustration

Q. 58

Expert-verified
Physics for Scientists and Engineers: A Strategic Approach with Modern Physics
Found in: Page 793

Answers without the blur.

Just sign up for free and you're in.

Illustration

Short Answer

For the circuit shown in FIGURE P28.58, find the current through and the potential difference across each resistor. Place your results in a table for ease of reading.

The results are in table:

See the step by step solution

Step by Step Solution

Step 1: Given Information

We need to find the current through and the potential difference across each resistor.

Step 2: Simplify   

When the resistors are connected one by one and without any junction between them then they are called to be connected in series. For a series of resistors, the equivalent resistance for their combination is given by an equation in the form

The two resistors and are in series. Using equation to get their equivalent resistance by

The current is the same for resistors in series. So the current through both resistors is calculated by using Ohm's law

Use Ohm's law to get the potential difference across each resistor of them by

And

Step 3: Simplify   

The two resistors are in series. so, equation to get their equivalent resistance by

The current is the same for resistance in series, so the current through both the resistance is calculated by using Ohm's law

Now, use Ohm's law to get the potential diffrence across each rsistor of them by,

And

Summerize the results in the next table

Recommended explanations on Physics Textbooks

94% of StudySmarter users get better grades.

Sign up for free
94% of StudySmarter users get better grades.