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Q. 12

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Physics for Scientists and Engineers: A Strategic Approach with Modern Physics
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Short Answer

A rectangle lies in the -plane. What is the magnitude of the electric flux through the rectangle if

a. ?

b. ?

a.

b.

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Step by Step Solution

Step 1 : Given information and Theory used 

Given :

Dimensions of rectangle :

a.

b.

Theory used :

The quantity of electric field passing through a closed surface is known as the Electric flux. Gauss's law indicates that the electric field across a surface is proportional to the angle at which it passes, hence we can determine charge inside the surface using the equation below.

(1)

Where is the angle formed between the electric field and the normal.

Step 2 : Calculating the required magnitude of the electric flux through the rectangle 

The rectangle is in -plane, this means the normal of the sheet is in direction which means, the area has component . We can get A, the area of the flat sheet by

(a) When the electric field would be , the electric flux will be :

(b)When the electric field would be , the electric flux will be :

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