Select your language

Suggested languages for you:
Log In Start studying!
Answers without the blur. Sign up and see all textbooks for free! Illustration


Physics for Scientists and Engineers: A Strategic Approach with Modern Physics
Found in: Page 1237

Answers without the blur.

Just sign up for free and you're in.


Short Answer

What energy (in MeV) alpha particle has a de Broglie wavelength equal to the diameter of nucleus?

The energy of the alpha particle is .

See the step by step solution

Step by Step Solution


Nuclear radius depends on mass number of nucleus as follows.

Here, is a constant and is mass number.

Substitute 1.2 fm for and 238 for , calculated the radius of nucleus.

Convert the unit for nuclear radius from fm to .

Diameter of the nucleus is,

From the given data, the de Broglie wavelength of the particle is equal to the diameter of the nucleus.


The de Broglie wavelength of alpha particle is,

Here, is Plank's constant and is momentum.

Rewrite this equation for momentum,

A moving particle has only kinetic energy, the relation between momentum and energy of the particle is,

Substitute for ,


Convert atomic mass of the particle from u to .

Substitute for for and for in the

equation .

Convert the units for energy from to .

Therefore, the energy of the alpha particle is .

Most popular questions for Physics Textbooks


Want to see more solutions like these?

Sign up for free to discover our expert answers
Get Started - It’s free

Recommended explanations on Physics Textbooks

94% of StudySmarter users get better grades.

Sign up for free
94% of StudySmarter users get better grades.