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Q. 14

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Physics for Scientists and Engineers: A Strategic Approach with Modern Physics
Found in: Page 415

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Short Answer

A block attached to a spring with unknown spring constant oscillates with a period of . What is the period if

a. The mass is doubled?

b. The mass is halved?

c. The amplitude is doubled?

d. The spring constant is doubled? Parts a to d are independent questions, each referring to the initial situation.

(a) When the mass is doubled, the period is

(b) When the mass is halved, the period is

(c) When the amplitude is doubled, it does not affect the time period

(d) When the spring constant is doubled, the period is decreases

See the step by step solution

Step by Step Solution

Step1: Find the time when the mass is doubled (part a)

Use angular frequency expression for spring mass system.

The periodic time is,

It Rewritten as

is doubled,

As a result, the periodic time is raised by times.

Step2: Find the time when the mass is halved (part b)

is halved then then,

so the time is of initial time.

Step3: Find the time when the amplitude is doubled (part c)

Because amplitude is independent of time, changes in amplitude have no effect on time.

Step4: Find the time when the spring constant is doubled (part d)

The time constant is inversely proportional to the periodic time,

so,

so the time decreased of initial time

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