Estimate the electric fields at points 1 and 2 in Figure Q26.5. Don’t forget that is a vector.
The electric field varies in the direction 1 to 2.
Theory used :
Electric Field is given by :
(a) We can see that the potential difference in , hence the field strength at this point will be . The formula is as follows:
(b) We can see that the potential difference in , hence the field strength at this location will be . The formula is as follows:
The vector will point to the left in both circumstances, parallel to the -axis.
Consider a uniformly charged sphere of radius R and total cAlC charge Q. The electric field outside the sphere is simply that of a point charge Q. In Chapter 24, we used Gauss's law to find that the electric field inside the sphere is radially outward with field strength
a. The electric potential outside the sphere is that of a point charge Q. Find an expression for the electric potentialat position r inside the sphere. As a reference, let at the surface of the sphere.
b. What is the ratio
c. Graph V versus r for 0 r 3 R.
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