Q. 9

Expert-verifiedFound in: Page 736

Book edition
4th

Author(s)
Randall D. Knight

Pages
1240 pages

ISBN
9780133942651

The two metal spheres in *Figure Q26.9* are connected by a metal wire with a switch in the middle. Initially the switch is open. Sphere 1, with the larger radius, is given a positive charge. Sphere 2, with the smaller radius, is neutral. Then the switch is closed. Afterward, sphere 1 has charge , is at potential , and the electric field strength at its surface is . The values for sphere 2 are .

a. Is larger than, smaller than, or equal to ? Explain.

b. Is larger than, smaller than, or equal to ? Explain.

c. Is larger than, smaller than, or equal to ? Explain.

a.

b.

c.

__Given :__

After the switch is closed,

Charge, potential and electric field strength of sphere 1 :

Charge, potential and electric field strength of sphere 1 : .

__Theory used__ :

Two proportional laws are :

(a) When the switch is closed, the charge is transferred from Sphere 1 to Sphere 2 until their potentials are equal, i.e.

.

(b) Because , the smaller sphere must carry less charge to have the same potential, hence .

c. For the electric field on the sphere's surface, we know that Because both spheres have the same potential, the sphere with the smaller radius will have the greater ratio. i.e.

.

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