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Q. 67

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Physics for Scientists and Engineers: A Strategic Approach with Modern Physics
Found in: Page 993

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Short Answer

A 25 g rubber ball is dropped from a height of 3.0 m above the center of a horizontal, concave mirror. The ball and its image coincide 0.65 s after the ball is released. What is the mirror’s radius of curvature?

Radius of curvature of the mirror is 0.93 m

See the step by step solution

Step by Step Solution

Step 1. Given information is :Mass of the rubber ball, m = 25g = 0.025 kgHeight above the center of the wall from where the ball is dropped, Initial velocity of the ball, Time after which the image coincides with the ball, 

We need to find out the radius of curvature of the mirror.

Step 3. Using the equation of motion.

The ball is under a constant acceleration that is gravitational acceleration.

Using figure, R can be calculated as :

Radius of curvature of the mirror is 0.93 m

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