A lens placed in front of an object creates an upright image twice the height of the object. The lens is then moved along the optical axis until it creates an inverted image twice the height of the object. How far did the lens move?
The lens will move .
We have given,
object distance from the lens = ,
image height = ,
image formed = upright.
We have to find how far did the lens move to obtain the inverted image.
Magnification of the lens
We know that for a lens to get an upright image that is 2 times magnified, the object is between the lens and the focal point.
After the lens has moved:
Using lens equation:
then, lens has moved=
An advanced computer sends information to its various parts via infrared light pulses traveling through silicon fibers. To acquire data from memory, the central processing unit sends a light-pulse request to the memory unit. The memory unit processes the request, then sends a data pulse back to the central processing unit. The memory unit takes to process a request. If the information has to be obtained from memory in , what is the maximum distance the memory unit can be from the central processing unit?
A tall object is in front of a diverging lens that has a focal length.
Use ray tracing to find the position and height of the image. To do this accurately, use a ruler or paper with a grid. Determine the image distance and image height by making measurements on your diagram. Calculate the image position and height. Compare with your ray-tracing answers in part .
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