Q.16

Expert-verified
Found in: Page 990

Physics for Scientists and Engineers: A Strategic Approach with Modern Physics

Book edition 4th
Author(s) Randall D. Knight
Pages 1240 pages
ISBN 9780133942651

FIGURE EX shows a transparent hemisphere with radius and index of refraction What is the maximum distance for which a light ray parallel to the axis refracts out through the curved surface?

A light ray parallel to the axis can refract out through the curved surface for a maximum distance

See the step by step solution

Step 1: Concepts and Principles

Total Internal Reflection occurs at the interface when the angle of incidence reaches a critical angle when a ray travels through a material with a higher index of refraction toward a material with a lower index.

Step 2: Given Data

• Hopefully we still have a glass spheroid and with a distance and an index of refraction of .
• A ray of light is going parallel to the hemisphere's axis.

Step 3: Required Data

An maximal distance d whereby the beam of light deforms out from the contour is necessary.

Step 4: Solution

The parameter of the hemispheric, derived by Equation, is the lowest angle in which the laser pulse deflects through the curved surface.

since then we really imagine a gyrus is just in wind and it is the hemisphere's index of refraction:

Step 5: maximum distance

An cosine of zero point could be found and used the topology as seen in Figure

Here where the angle of inclination is similar to total distance d at which light ray refracts on around a hemisphere's circular cylinder.

Step 6: Equation Comparison

Deduce the equation