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Q.88

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Physics for Scientists and Engineers: A Strategic Approach with Modern Physics
Found in: Page 335

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Short Answer

In FIGURE CP12.88, a 200 g toy car is placed on a narrow 60-cm-diameter track with wheel grooves that keep the car going in a circle. The 1.0 kg track is free to turn on a frictionless, vertical axis. The spokes have negligible mass. After the car’s switch is turned on, it soon reaches a steady speed of 0.75 m/s relative to the track. What then is the track’s angular velocity, in rpm?

Angular velocity of the track is 3.974 rev /min

See the step by step solution

Step by Step Solution

Step1: Given information

Mass of the toy =200 g =0.2 kg
Diameter of the track =60 cm =0.6 m So radius of track =0.3 m Mass of the frictionless track= 1 kg Speed relative to track (v)=0.75m/s

Step2: Explanation

First find the angular speed

From The law of conservation of angular momentum is constant

L = L'

Momentum = I x angular velocity

Now substitute the given values

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