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Q. 22

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Physics for Scientists and Engineers: A Strategic Approach with Modern Physics
Found in: Page 484

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Short Answer

Two loudspeakers emit sound waves along the x-axis. The

sound has maximum intensity when the speakers are 20 cm apart. The sound intensity decreases as the distance between the speakers is increased, reaching zero at a separation of 60 cm.

a. What is the wavelength of the sound?

b. If the distance between the speakers continues to increase, at

what separation will the sound intensity again be a maximum?

a. The wavelength of the sound is

b. If the distance between the speakers continues to increase, the sound intensity again be a maximum when the separation is

See the step by step solution

Step by Step Solution

Part a Step 1: Given data

For maximum intensity, distance between speakers is

For zero intensity, distance between speakers is

Step 2: Determination of wavelength

We know that the interference of waves occurs due to the phase difference between two waves.

Therefore, according to the condition of interference, if is the wavelength of the sound wave, then we can write,

Part b Step 2: Introduction

For interference of waves, the distance between two maxima or minima is equal to the wavelength of the sound wave.

Step 2: Determination of the separation between the speakers

Initially, the difference between two speakers for maximum intensity was

Wavelength of the sound wave is

Therefore, if the distance between the speakers is increased, the distance between the speakers should be, when the speakers will be at maximum intensity again.

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