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Q. 22

Expert-verified
Found in: Page 484

### Physics for Scientists and Engineers: A Strategic Approach with Modern Physics

Book edition 4th
Author(s) Randall D. Knight
Pages 1240 pages
ISBN 9780133942651

# Two loudspeakers emit sound waves along the x-axis. Thesound has maximum intensity when the speakers are 20 cm apart. The sound intensity decreases as the distance between the speakers is increased, reaching zero at a separation of 60 cm.a. What is the wavelength of the sound?b. If the distance between the speakers continues to increase, atwhat separation will the sound intensity again be a maximum?

a. The wavelength of the sound is

b. If the distance between the speakers continues to increase, the sound intensity again be a maximum when the separation is

See the step by step solution

## Part a Step 1: Given data

For maximum intensity, distance between speakers is

For zero intensity, distance between speakers is

## Step 2: Determination of wavelength

We know that the interference of waves occurs due to the phase difference between two waves.

Therefore, according to the condition of interference, if is the wavelength of the sound wave, then we can write,

## Part b Step 2: Introduction

For interference of waves, the distance between two maxima or minima is equal to the wavelength of the sound wave.

## Step 2: Determination of the separation between the speakers

Initially, the difference between two speakers for maximum intensity was

Wavelength of the sound wave is

Therefore, if the distance between the speakers is increased, the distance between the speakers should be, when the speakers will be at maximum intensity again.