Engineers are testing a new thin-film coating whose index of refraction is less than that of glass. They deposit a 560-nm-thick layer on glass, then shine lasers on it. A red laser with a wavelength of 640 nm has no reflection at all, but a violet laser with a wavelength of 400 nm has a maximum reflection. How the coating behaves at other wavelengths is unknown. What is the coating’s index of refraction?
The coating's index of refraction is n= 1.429
The change in direction of a wave passing from one medium to another or from a gradual change in the medium is known as the refraction.
Thus, the solution of the refraction is
Thus, the ratio of the constructive interference is
In order to find out the substitute of the by the random numbers of . Thus, the substitute of is 3.
By using the coating's index of refraction in equation is
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