The electric field strength is inside a parallel-plate capacitor with a spacing. A proton is released from rest at the positive plate. What is the proton’s speed when it reaches the negative plate?
The proton's final velocity at negative plate is
Electric field strength is .
Spacing is .
The objective is to find proton's speed reaches the negative plate.
The particle travels along the field, more toward the capacitor's deleterious anode, in a static electric field. At the expenditure of electrostatic field, it gains angular momentum.
The variation in electromotive force can be computed using equation :
We can compute the proton's mobility when it approaches the negatively pole by transforming the difference in electromotive force energy into kinetic energy.
From energy conversation
Two protons are launched with the same speed from point 1 inside the parallel-plate capacitor of FIGURE Q25.4. Points 2 and 3 are the same distance from the negative plate.
a. Is , the change in potential energy along the path , larger than, smaller than, or equal to ?
b. Is the proton's speed at point 2 larger than, smaller than, or equal to ? Explain.
Two-diameter electrodes apart form a parallel plate capacitor. The electrodes are attached by metal wires to
the terminals of a battery. After a long time, the capacitor is disconnected from the battery but is not discharged. What are the charge on each electrode, the electric field strength inside the capacitor, and the potential difference between the electrodes
a. Right after the battery is disconnected?
b. After insulating handles are used to pull the electrodes away from each other until they are apart?
c. After the original electrodes (not the modified electrodes of part b) are expanded until they are in diameter?
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