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Q. 3

Physics for Scientists and Engineers: A Strategic Approach with Modern Physics
Found in: Page 709

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Short Answer

A proton is released from rest at the positive plate of a parallelplate capacitor. It crosses the capacitor and reaches the negative plate with a speed of 50,000 m/s. What will be the final speed of an electron released from rest at the negative plate?

The object's final speed is

See the step by step solution

Step by Step Solution

Step :1 Electrostatic field  

Given information:

A proton speed reaches the negative place is .


The objective is to find final speed of proton.

We can estimate the changes in electric field seen between favourable and unfavourable plates for the electron using alternative energy:

We could obtain the quantity by situating the minus panel at and therfore the optimistic plate at using equation :

Step :2 Gravitational potential

The gravitational potential shift has been converted into energy.

From the angle of reducing emissions:

Step :3 Substitution 

Substituting the determined value from either the proton case:

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