A proton is released from rest at the positive plate of a parallelplate capacitor. It crosses the capacitor and reaches the negative plate with a speed of 50,000 m/s. What will be the final speed of an electron released from rest at the negative plate?
The object's final speed is
A proton speed reaches the negative place is .
The objective is to find final speed of proton.
We can estimate the changes in electric field seen between favourable and unfavourable plates for the electron using alternative energy:
We could obtain the quantity by situating the minus panel at and therfore the optimistic plate at using equation :
The gravitational potential shift has been converted into energy.
From the angle of reducing emissions:
Substituting the determined value from either the proton case:
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