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Q.45

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Physics for Scientists and Engineers: A Strategic Approach with Modern Physics
Found in: Page 711

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Short Answer

An arrangement of source charges produces the electric potential

V = 5000x2 along the x-axis, where V is in volts and x is in meters.

What is the maximum speed of a 1.0 g, 10 nC charged particle that moves in this potential with turning points at +-8.0 cm?

The maximum Speed of Particle is 2.53 cm/s

See the step by step solution

Step by Step Solution

Step 1: Concept

The electric potential energy and electric Potential difference the related through given equation;

U= qV

Step 2: Unit Conversion

Here in this Question given Mass particle is;

And, the charge of particle is;

Step 3: Calculation of Maximum Speed

Due the arrangement of the sources electric charges which are produced are;

Here in this Equation V is in Volt and X is in meters

As charged particle moves at turning point at 8cm

Which denotes that;

At this Point Partcle will have only Potential energy, there will be no Kinetic energy.

Thus the Max Potential energy is;

At the time hence the particle comes back to the origin x=0, the potential energy converted into kinetic energy

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