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Q 41

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Physics for Scientists and Engineers: A Strategic Approach with Modern Physics
Found in: Page 1083

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Short Answer

A 222Rn atom (radon) in a 0.75 T magnetic field undergoes radioactive decay, emitting an alpha particle in a direction perpendicular to . The alpha particle begins cyclotron motion with a radius of 45 cm. With what energy, in MeV, was the alpha particle emitted?

The energy of alpha particle emitted is 5.49 MeV

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Step by Step Solution

Step 1. Given information is :Magnetic field = 0.74 TRadius of initial cyclotron motion = 45 cm

We need to find out the energy of alpha particle emitted.

Step 2. Using the equilibrium condition between centripetal force and magnetic force

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