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Q 43

Physics for Scientists and Engineers: A Strategic Approach with Modern Physics
Found in: Page 1083

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Short Answer

In a head-on collision, the closest approach of a 6.24 MeV alpha particle to the center of a nucleus is 6.00 fm. The nucleus is in an atom of what element? Assume the nucleus remains at rest.

The element is Aluminum

See the step by step solution

Step by Step Solution

Step 1. Given information is :Kinetic energy of alpha particle = 6.24 MeVClosest approach = 6.00 fm

We need to find out the element used.

Step 2. Comparing Kinetic and potential energy for the closest approach

Let Z be the atomic number of the element.

At the closest approach, Kinetic energy will be equal to the potential energy. Therefore,

Z = 13 for Aluminum

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