FIGURE Q37.6 shows a magnetic field between two parallel, charged electrodes. An electron with speed passes between the plates, from left to right, with no deflection. If a proton is fired toward the plates with the same speed ,will it be deflected up, deflected down, or pass through with no deflection? Explain.
Proton will pass through plates with no deflection.
We have given that an electron with speed v0 is passed through oppositely charged plates having magnetic field between them . The electron passes left to right without deflection.
We all know that charge on electron and proton is same. Now, the electron and proton both are fired towards the plates having uniform magnetic and electric field with same velocities and parallel to the plates due to which force applied by magnetic field will be same as that applied by electric field but in opposite direction. So the path of proton will be same as that of electron i.e. straight without any deflection.
An electron in a cathode-ray beam passes between -long parallel-plate electrodes that are apart. A , -wide magnetic field is perpendicular to the electric field between the plates. The electron passes through the electrodes without being deflected if the potential difference between the plates is
a. What is the electron’s speed?
b. If the potential difference between the plates is set to zero, what is the electron’s radius of curvature in the magnetic field?
Firecrackers A and B are 600 m apart. You are standing exactly halfway between them. Your lab partner is 300 m on the other side of firecracker A. You see two flashes of light, from the two explosions, at exactly the same instant of time. Define event 1 to be “firecracker A explodes” and event 2 to be “firecracker B explodes.” According to your lab partner, based on measurements he or she makes, does event 1 occur before, after, or at the same time as event 2? Explain.
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