Magnetic resonance imaging needs a magnetic field strength of . The solenoid is long and in diameter. It is tightly wound with a single layer of diameter superconducting wire. What size current is needed?
The current needed is
We have given,
Magnetic field strength =
We have to find the current through the solenoid.
We know the magnetic field which is produced by uniform shape solenoid at its center.
The magnetic field is
where N is the no. of turns and L is the length of the solenoid.
Then current will be,
a. In FIGURE P29.76, a long, straight, current-carrying wire of linear mass density is suspended by threads. A magnetic field perpendicular to the wire exerts a horizontal force that deflects the wire to an equilibrium angle . Find an expression for the strength and direction of the magnetic field .
b. What deflects a 55 g/m wire to a 12° angle when the current is 10 A?
The heart produces a weak magnetic field that can be used to diagnose certain heart problems. It is a dipole field produced by a current loop in the outer layers of the heart.
a. It is estimated that the field at the center of the heart is . What current must circulate around an -diameter loop, about the size of a human heart, to produce this field?
b. What is the magnitude of the heart’s magnetic dipole moment.
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