The two 10-cm-long parallel wires in FIGURE EX29.34 are separated by 5.0 mm. For what value of the resistor R will the force between the two wires be 5.4 * 10-5 N?
Two current -carrying wires generate forces between them since ordinary currents produce magnetic fields and this fields exert significant forces on ordinary currents. The forces on the wires re equal in magnitude and it is given by equation (29.27) in the form
where d is the distance between the two wires and is the length of the wire were both wires have the same length, The force is attractive if the current are in the same direction and repulsive if they are in opposite directions.
We can assume that the current in the left circuit is , so we use Ohms law to get this current as Ohm's law states that the current flows through a resistance due to the potential difference between the resistance.
let us determine the current through the left wire using the values for and of the battery by
We rearrange equation(1) for to be in the form
Where is the current in right wire. Now, plug the values for into equation(3) to get
Again we use the Ohms law to get the resistance in the right circuit by using the value of the potential difference .
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