A square current loop on each side carries a current. The loop is in a uniform magnetic field. The axis of the loop, perpendicular to the plane of the loop, is ° away from the field direction. What is the magnitude of the torque on the current loop?
The magnitude of the torque on the current loop is .
We need to find the magnitude of the torque on the current loop.
The torque represents the magnitude of the force multiplied by the distance between the axis and the line of the action. A current loop inside a magnetic field experiences a torque that is exerted by the magnetic force and the loop starts to rotate. For a square loop with , its torque is given by equation () in the form :
Where represents the area of the loop, is the current in the loop and is the angle between the magnetic field and the magnetic dipole moment of the loop.
When the dipole moment is parallel to the magnetic field, the torque is zero and it is maximum when the dipole moment is perpendicular to the magnetic field. Now, we plug the values for into equation () to get as .
Particle accelerators, such as the Large Hadron Collider, use magnetic fields to steer charged particles around a ring. Consider a proton ring with 36 identical bending magnets connected by straight segments. The protons move along a -m-long circular arc as they pass through each magnet. What magnetic field strength is needed in each magnet to steer protons around the ring with a speed of ? Assume that the field is uniform inside the magnet, zero outside.
94% of StudySmarter users get better grades.Sign up for free