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Q.4

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Physics for Scientists and Engineers: A Strategic Approach with Modern Physics
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Short Answer

An electron moves along the with . As it passes the origin, what are the strength and direction of the magnetic field at the positions. (a) (1 cm, 0 cm, 0 cm) (b) (o cm, o cm, 1 cm)

(c) ( 0 cm, 1 cm, 1 cm)?

The strength and magnetic field at

(a)

(b)

(c)

See the step by step solution

Step by Step Solution

Step 1:   Blot-Savart Law 

A moving charge produces the magnetism. To compute the magnetism at a specific location, use the Blot Savart law. The transfer function becomes multiplied because of radial and path length dimensions are always perpendicular. The magnetic force due to a given direction in the form is formed.

This same angles between of area's axis and also the charge's rate is zero

Step 2: Direction and Velocity 

The torque generated either by destination's direction and the mount's velocity is

Step 3: Positive Direction

The torque generated by the destination's axis or the mount's velocity is. The range again from original really does have a significance of

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