Q.22

Expert-verifiedFound in: Page 451

Book edition
4th

Author(s)
Randall D. Knight

Pages
1240 pages

ISBN
9780133942651

A hammer taps on the end of a 4.00-m-long metal bar at room temperature. A microphone at the other end of the bar picks up two pulses of sound, one that travels through the metal and one that travels through the air. The pulses are separated in time by 9.00 ms . What is the speed of sound in this metal?

The speed of sound in the metal bar is 1502.74 m/s.

The length of the metal bar is

The time separation between the pulses is

The velocity of the sound wave in air is

The formula to calculate the time taken through the air is given by

Substitute 4m for d and 343 m/s for into the above formula to calculate the time taken .

The separation time of the two pulses is given by where t_{1} is the time taken by the pulses travelling through the metal bar

Substitute 0.01166s for t_{2} and for into the above formula to calculate the time taken by the pulses through the bar.

The formula to calculate the velocity of the sound through the material is given by :

Substitute 4m for d and for t_{1} into the above formula to calculate the velocity.

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