Log In Start studying!
Answers without the blur. Sign up and see all textbooks for free! Illustration

Q. 4

Physics for Scientists and Engineers: A Strategic Approach with Modern Physics
Found in: Page 954

Answers without the blur.

Just sign up for free and you're in.


Short Answer

FIGURE Q33.5 shows the light intensity on a viewing screen behind a single slit of width a The light's wavelength is. Is, or is it not possible to tell? Explain

a) The light wavelength is remains the same

b)The lambda less than a is remains the same

c) The lambda equal to a is decrease

d)The lambda greater than a is increase

See the step by step solution

Step by Step Solution

Step1: The light wavelength(part a)

We will use some of the expressions from Young's Double-Slit Experiment chapter in the book in this problem.

Slits are replaced with slits, and the spacing d between adjacent slits remains constant.

Expression from the angles of bright fringes:

For constant angular positions of the bright fringes in the interference pattern and spacing d, m represents the number of fringes that will remain constant.

Step2: Find fringe spacing(part b)

Fringe spacing expression:

Fringe spacing is independent of the number of slits, and for constant spacing d between slits, fringe spacing remains constant.

 step3: Find  (part c) 

We don't need a physics expression to assume that as the number of slits increases from to, the width of each fringe decreases while the spacing d remains constant.

Step4: Find(part d)

d) Intensity from expression:

Because brightness intensity is proportional to the square of the amplitude N but not to the number of slits, the brightness of each fringe increases for constant spacing d.

Recommended explanations on Physics Textbooks

94% of StudySmarter users get better grades.

Sign up for free
94% of StudySmarter users get better grades.