Light of wavelength illuminates a double slit, and the interference pattern is observed on a screen. At the position of the bright fringe, how much farther is it to the more distant slit than to the nearer slit
Distance of distant slit than to the nearer slit is.
The path difference between the two slits to the fringe is an integral number of light wavelengths, constructive interference occurs, resulting in vivid fringes.
When the route difference is a half-integral number of wavelengths, destructive interference and dark fringes occur.
To find path difference first we calculate phase difference.
Phase difference is,
is number of bright fringe
Optical computers require microscopic optical switches to turn signals on and off. One device for doing so, which can be implemented in an integrated circuit, is the Mach-Zender interferometer seen in FIGURE. Light from an on-chip infrared laser is split into two waves that travel equal distances around the arms of the interferometer. One arm passes through an electro-optic crystal, a transparent material that can change its index of refraction in response to an applied voltage. Suppose both arms are exactly the same length and the crystal’s index of refraction with no applied voltage is.
a. With no voltage applied, is the output bright (switch closed, optical signal passing through) or dark (switch open, no signal)? Explain.
b. What is the first index of refraction of the electro-optic crystal larger than that changes the optical switch to the state opposite the state you found in part a?
94% of StudySmarter users get better grades.Sign up for free