Question: A rotating wheel requires rotating through 37.0 revolutions. Its angular speed at the end of the interval is. What is the constant angular acceleration of the wheel?
The solution of the constant angular acceleration is .
First converting units:
Multiply the angular speed by a conversion factor to convert its units from
(rev/min) to (rad/sec)
Second, solving the problem:
Model the wheel as a rigid object under constant angular acceleration and use the following equation to find the initial angular speed.
Substitute the known numerical values.
Use the following equation to find the angular acceleration of the wheel:
Solve for .
Substitute for from Equation (1) in Equation (2).
Substitute numerical values.
Hence, the answer is .
A uniform solid disk of mass m=3.00Kg and radius r=0.200m rotates about a fixed axis perpendicular to its face with angular frequency 6.00rad/s. Calculate the magnitude of the angular momentum of the disk when the axis of rotation (a) passes through its centre of mass and (b) passes through a point midway between the centre and the rim.
Two children are playing with a roll of paper towels.One child holds the roll between the index fingersof her hands so that it is free to rotate, and the second child pulls at constant speed on the free end ofthe paper towels. As the child pulls the paper towels,the radius of the roll of remaining towels decreases.
(a) How does the torque on the roll change with time?(b) How does the angular speed of the roll change in time? (c) If the child suddenly jerks the end paper towel with a large force, is the towel more likely to break from the others when it is being pulled from an early full roll or from a nearly empty roll?
A particle of mass 0.400Kg is attached to the 100cm mark of a meterstick of mass 100Kg . The meterstick rotates on the surface of a frictionless, horizontal table with an angular speed of 4.00rad/s. Calculate the angular momentum of the system when the stick is pivoted about an axis (a) perpendicular to the table through the mark 50.0cm and (b) perpendicular to the table through the 0cm mark.
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