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Q. 79- Excercises And Problems

Physics For Scientists & Engineers
Found in: Page 746

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Short Answer

Bead A has a mass of 15 g and a charge of -5.0nC. Bead B has a mass of 25 g and a charge of-10.0nC. The beads are held12 cm apart (measured between their centers) and released. What maximum speed is achieved by each bead?

- Maximum speed achieved by band A is 1.77 cm/s.

- Maximum speed achieved by band B is1.06 cm/s.

See the step by step solution

Step by Step Solution

Step 1: Given information

ma=15gmmu=25gmqa=-5×10-7C4a=-10×10-9Cr=12 cm

We know that initial energy of system is


WhereEi-Initial energy of the system

qa =charge on bead a de

qt= charge on bead b

K= distance l in meters

Final energy of system is kinetic energy


ma= mass of bead a

mb= mass of bead b

Va=velocity of bead a

vb =velocity of bead b

Step 2: Calculation

According to energy conservation, Initial energy final energy Ei=Ef

Plugging the values in the above equation,14πϵ04aqur=12mava2+12mbvb2.(1)

According to law of conservation of momentum



Putting (2) in (1)



Putting the given values,


localid="1650117105638" role="math" =1.77 m/s

Using Eq. (2)


vb =1.06

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