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Physics For Scientists & Engineers
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Short Answer

A plastic sphere floats in water with 50% of its volume submerged. This same sphere floats in glycerin with 40% of its volume submerged. Determine the densities of (a) the glycerin and (b) the sphere.

(a) The density of glycerin is 1250 kg/m3.

(b) The density of the sphere is 500 kg/m3.

See the step by step solution

Step by Step Solution

Given data:

Percentage of volume of sphere submerged in water is 50%.

Percentage of volume of sphere submerged in glycerin is 40%.

Buoyancy and gravitational force:

The buoyant force from a liquid of density d when volume of the liquid displaced v is,

B=dgv ..…(I)

Here, g is the acceleration due to gravity having value,

g=9.8 m/s2

The gravitational force on a body of volume v and density d is,

role="math" localid="1663748724511" F=dvg ..... (II)

(a) Determining the density of glycerin:

Let the volume of the sphere be V and its density be ds. Volume of water displaced is V2. Density of water is 1000 kg/m3. Since the sphere is in equilibrium, equate equations (I) and (II) to get

Volume of displaced glycerin is .

Let the density of glycerin be .

Since the sphere is in equilibrium, equate equations (I) and (II) to get

dsVg=1000 kg/m3×V2×gds=500 kg/m3

Thus, the required density is,

410V=0.4V

Let the density of glycerin be dg.

Since the sphere is in equilibrium, equate equations (I) and (II) to get

dsVg=dg×0.4V×g

dg=ds0.4=5000.4 kg/m3=1250 kg/m3

Thus, the required density is 1250 kg/m3.

(b) Determining the density of sphere:

This has already been calculated in the previous step. The required density is 500 kg/m3.

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