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Physics For Scientists & Engineers
Found in: Page 443

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Short Answer

(a.) Calculate the absolute pressure at an ocean depth of 1 000 m. Assume the density of seawater is 1030 kg/m3and the air above exerts a pressure of 101.3 kpa.

(b.) At this depth, what is the buoyant force on a spherical submarine having a diameter of 5.00 m?

(a) The absolute pressure at an ocean depth is P=1.00pa

(b) The buoyant force on a spherical submarine is B19.5×109N

See the step by step solution

Step by Step Solution

Step 1:

The pressure in a fluid at rest varies with depth h in the fluid according to the expression:

P=P0+ρgh

Where, P0 is the pressure at h=0 and ρ the density of the fluid is assumed uniform. Pascal’s law states that when pressure is applied to an enclosed fluid, the pressure is transmitted undiminished to every point in the fluid and to every point on the walls of the container.

When an object is partially or fully submerged in a fluid, the fluid exerts on the object an upward force called the buoyant force. According to Archimedes’s principle, the magnitude of the buoyant force is equal to the weight of the fluid displaced by the object:

B=ρfluidgVfluid

Step 2:

Given:

Part (a):

Depth of ocean h=1000 m

Density of water ρ=1030 kg/m3

Pressure of air P0=101.3 kpa

By using concept and the formula from step (1), we get

P=P0+ρghP=101.3×103+1000×1030×9.8P=1.00pa

Step 3:

Given:

Part (b):

Depth of ocean h=1000 m

Density of water ρ=1030 kg/m3

Diameter of submarine D=5 m

Radius of submarine r=D2=2.5 m

By using concept and the formula from step (1), we get

B=ρfluidgVfluidB=ρfluidg×AhB=ρfluidg×π×r2×hB=101.3×103×9.8×3.14×2.52×1000B19.5×109N

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