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96 P

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Physics For Scientists & Engineers
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Short Answer

A chain of length L and total mass M is released from rest with its lower end just touching the top of a table as shown in Figure P9.96a. Find the force exerted by the table on the chain after the chain has fallen through a distance x as shown in Figure P9.96b. (Assume each link comes to rest the instant it reaches the table.

The total force exerted by the table on chain during falling distance x is 3MgxL.

See the step by step solution

Step by Step Solution

Step 1: Identification of given data

The mass of chain is M

The length of chain is L

The distance fallen by the chain through hole is x

Step 2: Linear Mass Density

The linear mass density of an object is the mass of the unit length of the object. it is given as –

λ=ML

Step 3: Determination of force exerted by table on the chain

The mass of small element of chain is given as:

dm=λ·dx=MLdx

The weight of chain length fallen is given as:

dw=λgx=MLgx

The speed of the chain after falling distance x is given as:

v=2gx

The force exerted on chain after falling distance x is given as:

F=vdmdt

For the given values, the above equation becomes-

F=vMLdxdt=MLvdxdt=MLvv=MLv2

solving further,

F=ML2gx2F=2MgxL

The total force exerted by the table on chain during falling distance x is given as:

Ft=F+w

For the given values, the above equation becomes-

Ft=2MgxL+MgxL=3MgxL

Therefore, the total force exerted by table on chain during falling distance x is 3MgxL .

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