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Physics For Scientists & Engineers
Found in: Page 78

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Short Answer

Mayan kings and many school sports teams are named for the puma, cougar, or mountain lionFelis concolor the best jumper among animals. It can jump to a height of 12.0 ftwhen leaving the ground at an angle of 45.0°. With what speed, in units, does it leave the ground to make this leap?

The initial velocity of the speed is vi=12 m/s.

See the step by step solution

Step by Step Solution

Step 1: Definition of initial velocity.

  • The initial velocity, denoted by u, is the velocity at time interval t=0. It's the speed at which the motion begins.
  • The starting velocity is articulated as u=v-at if time, acceleration, and final velocity are provided.
  • Where u is the initial velocity , v is the final velocity,is the time taken, and a is the acceleration

Step 2: Find the time required to reach this height.

Given data,

ymax=12ftymax=123.28ymax=3.66 m

First, we need to find the time required to reach this height which we get by using this equation:


Solving t for taking into account that at the maximum height vy=0 and a=-g:


Step 3: Find the vertical displacement.

Then, we need to find the vertical displacement made in this time by using the following equation:


Step 4: Determine the initial velocity.

By knowing the angle of projection , we can find the initial velocity by using the following relation:

Therefore, the initial velocity of the speed is vi=12 m/s.

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