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Physics For Scientists & Engineers
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Short Answer

A simple pendulum has a period of 2.5 s. (i) what is its period if its length is made four times larger? (a) 1.25 s (b) 1.77 s (c) 2.5 s (d) 3.54 s (e) 5 s (ii) What is its period if the length is held constant at its initial value and the mass of the suspended bob is made four times larger? Choose from the same possibilities.

(a)The period if its length is made four times larger isTf=2Ti=2×2.5s=5s, Hence option (e) is the correct answer for this question.

(b) The period if the length is held constant at its initial value and the mass of the suspended bob is made four times larger isTf=Ti=2.5s, Hence option (c) is the correct answer for this question.

See the step by step solution

Step by Step Solution

Step 1: Relationship between the length and time 

A simple pendulum of length L can be modeled to move in simple harmonic motion for small angular displacements from the vertical. Its period is

T=2πLg

T=Period of oscillation

L=Length of pendulum

g=Gravitational acceleration

Step 2(i): Find the period if its length is made four times larger

From step (1), we have

Ti=2πLigand Tf=2πLfg, where i and f stands for initial and final respectively.

Tf=2π4LigTf=2.2πLigTf=2Ti

The period becomes larger by a factor of 2, to become 5 s.

Hence option (e) is the correct answer for this question.

Step 3(ii): Find the period if the length is held constant at its initial value and the mass of the suspended bob is made four times larger

Changing the mass has no effect on the period of a simple pendulum.

Hence option (c) is the correct answer for this question.

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