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Q16OQ

Expert-verifiedFound in: Page 473

Book edition
9th Edition

Author(s)
Raymond A. Serway, John W. Jewett

Pages
1624 pages

ISBN
9781133947271

**A simple pendulum is suspended from the ceiling of a stationary elevator, and the period is determined. (i) When the elevator accelerates upward, is the period (a) greater, (b) smaller, or (c) unchanged? (ii) When the elevator has a downward acceleration, is the period (a) greater, (b) smaller, or (c) unchanged? (iii) When the elevator moves with constant upward velocity, is the period of the pendulum (a) greater, (b) smaller, or (c) unchanged?**

(i) The elevator accelerates upward the period is small; Hence option (b) is the correct answer for this question.

(ii) The elevator has a downward acceleration the period is greater; Hence option (a) is the correct answer for this question.

(iii) The elevator moves with constant upward velocity the period of the pendulum is unchanged; hence option (c) is the correct answer for this question.

A simple pendulum of length L can be modeled to move in simple harmonic motion for small angular displacements from the vertical. Its period is

$T=2\pi \sqrt{\frac{L}{g}}$

$T=$Period of oscillation

$L=$Length of pendulum

$g=$Gravitational acceleration

From step (1), we have

$T=2\pi \sqrt{\frac{L}{g}}$

The upward acceleration has the same effect as an increased gravitational acceleration.

The elevator accelerates upward the period is small; Hence option (b) is the correct answer for this question.

The downward acceleration has the same effect as a decreased gravitational acceleration.

The elevator has a downward acceleration the period is greater; Hence option (a) is the correct answer for this question.

The absence of acceleration means that the effective gravitational field is the same as that for a stationary elevator.

The elevator moves with constant upward velocity the period of the pendulum is unchanged; Hence option (c) is the correct answer for this question.

** **

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