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Physics For Scientists & Engineers
Found in: Page 472

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Short Answer

If a simple pendulum oscillates with small amplitude and its length is doubled, what happens to the frequency of its motion? (a) It doubles. (b) It becomes times 2 as large. (c) It becomes half as large. (d) It becomes times 12as large. (e) It remains the same.

Option (d) is the correct answer, i.e it becomes times 12as larger.

See the step by step solution

Step by Step Solution

Step 1: Relationship between amplitude and length

A simple pendulum of length L can be modeled to move in simple harmonic motion for small angular displacements from the vertical. Its period is


T=Period of oscillation

L=Length of pendulum

g=Gravitational acceleration

Step 2: Find what will happen when its length is doubled if a simple pendulum oscillates with small amplitude

The period of a simple pendulum is

T=2πLg, and its frequency is f=1T=12πgL

Thus, if the length is doubled sol'=2l , the new frequency is



Hence option (d) is the correct answer for this question.

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