Suggested languages for you:

Americas

Europe

Q26P

Expert-verifiedFound in: Page 382

Book edition
9th Edition

Author(s)
Raymond A. Serway, John W. Jewett

Pages
1624 pages

ISBN
9781133947271

**A steel wire of diameter 1 mm can support a tension of 0.2 kN. A steel cable to support a tension of 20 kN should have diameter of what order of magnitude?**

As a result, the cable's diameter is $=1\text{mm}\sqrt{100}$

$~1\text{cm}$

The diameter of the steel wire is 1mm in this case. $={10}^{-3}\text{m}$

${F}_{1}=0.2\text{kN}$ is the tension force.$=0.2\times {10}^{3}\text{N}$

The cable has a tension force of ${F}_{2}=20\text{kN}$.

Because all of the wires are bundled together, they can withstand almost identical stress.

As a result, the number of wires$\text{}=\frac{20\text{kN}}{0.2\text{N}}$

The cable's cross-sectional area is equal to the difference of the cable's diameter.

As a result, the cable's diameter is $=1\text{mm}\sqrt{100}$ $~1\text{cm}$

94% of StudySmarter users get better grades.

Sign up for free