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Expert-verified Found in: Page 383 ### Physics For Scientists & Engineers

Book edition 9th Edition
Author(s) Raymond A. Serway, John W. Jewett
Pages 1624 pages
ISBN 9781133947271 # The deepest point in the ocean is in the Mariana Trench, about 11 km deep, in the Pacific. The pressure at this depth is huge, about 1.13 3 108 N/m2. (a) Calculate the change in volume of 1.00 m3 of seawater carried from the surface to this deepest point. (b) The density of seawater at the surface is 1.03 3 103 kg/m3. Find its density at the bottom. (c) Explain whether or when it is a good approximation to think of water as incompressible.

a) the change in volume $=1,128.987×{10}^{5}\text{N}/{\text{m}}^{2}$

b) B is the bulk modules of sea water is as follows:

$B=2.34×{10}^{9}\text{N}/\text{m}2$

c) Bulk modules are familiar to us. $=\frac{-\left(1,128.987×{10}^{5}\text{N}/{\text{m}}^{2}\right)×\left(0.9{\text{m}}^{3}\right)}{2.34×{10}^{9}\text{N}/{\text{m}}^{2}}$

See the step by step solution

## Step 1:

In the surface pressure is ${P}_{s}=1.013×{10}^{5}\text{N}/{\text{m}}^{2}$

In the depth pressure is ${P}_{d}=1.13×{10}^{8}\text{N}/{\text{m}}^{2}$

pressure variation

$\begin{array}{l}{\Delta }_{p}={P}_{S}-{P}_{d}\\ =1.13×{10}^{8}-1.013×{10}^{5}\\ =1,128.987×{10}^{5}\text{N}/{\text{m}}^{2}\end{array}$

B is the bulk modules of sea water is as follows:

$B=2.34×{10}^{9}\text{N}/\text{m}2$

Bulk modules are familiar to us.

$\begin{array}{l}B=\frac{\left(-\Delta p\right){v}_{0}}{\Delta v}\\ \Delta v=\frac{-\left(\Delta P\right){v}_{0}}{B}\\ =\frac{-\left(1,128.987×{10}^{5}\text{N}/{\text{m}}^{2}\right)×\left(0.9{\text{m}}^{3}\right)}{2.34×{10}^{9}\text{N}/{\text{m}}^{2}}\end{array}$ ### Want to see more solutions like these? 