Book edition 9th Edition

Author(s) Raymond A. Serway, John W. Jewett

Pages 1624 pages

ISBN 9781133947271

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Short Answer

The deepest point in the ocean is in the Mariana Trench, about 11 km deep, in the Pacific. The pressure at this depth is huge, about 1.13 3 108 N/m2.
(a) Calculate the change in volume of 1.00 m3 of seawater carried from the surface to this deepest point.
(b) The density of seawater at the surface is 1.03 3 103 kg/m3. Find its density at the bottom.
(c) Explain whether or when it is a good approximation to think of water as incompressible.

a) the change in volume $= 1, 128.987 \times 10^{5} N / m^{2}$

b) B is the bulk modules of sea water is as follows:

$B = 2.34 \times 10^{9} N / m 2$

c) Bulk modules are familiar to us. $= \frac{- (1, 128.987 \times 10^{5} N / m^{2}) \times (0.9 m^{3})}{2.34 \times 10^{9} N / m^{2}}$

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Step by Step Solution

TABLE OF CONTENTS :

TABLE OF CONTENTS

Step 1:

In the surface pressure is $P_{s} = 1.013 \times 10^{5} N / m^{2}$

In the depth pressure is $P_{d} = 1.13 \times 10^{8} N / m^{2}$

pressure variation

$\begin{array}{l} Δ_{p} = P_{S} - P_{d} \\ = 1.13 \times 10^{8} - 1.013 \times 10^{5} \\ = 1, 128.987 \times 10^{5} N / m^{2} \end{array}$

B is the bulk modules of sea water is as follows:

$B = 2.34 \times 10^{9} N / m 2$

Bulk modules are familiar to us.

$\begin{array}{l} B = \frac{(- Δ p) v_{0}}{Δ v} \\ Δ v = \frac{- (Δ P) v_{0}}{B} \\ = \frac{- (1, 128.987 \times 10^{5} N / m^{2}) \times (0.9 m^{3})}{2.34 \times 10^{9} N / m^{2}} \end{array}$

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