Book edition 9th Edition

Author(s) Raymond A. Serway, John W. Jewett

Pages 1624 pages

ISBN 9781133947271

Answers without the blur.

Just sign up for free and you're in.

Short Answer

A system consists of three particles, each of mass $5.00 g$ , located at the corners of an equilateral triangle with sides of $30.0 c m$ . (a) Calculate the potential energy of the system. (b) Assume the particles are released simultaneously. Describe the subsequent motion of each. Will any collisions take place? Explain.

(a) Total potential energy of the system will be $U_{T o t a l} = - 1.67 \times 10^{- 17} J$

(b) All particles will collide with each other at the center of the triangle.

See the step by step solution

Step by Step Solution

TABLE OF CONTENTS :

TABLE OF CONTENTS

Step 1: Conservation of energy

The conservation of energy says that’s the total energy in the initial condition of the object will be equal to the total energy in the final condition.

$\begin{array}{rcl} {(K + U)}_{i n i t i a l} & = & {(K + U)}_{f i n a l} \\ K & = & k i n e t i c e n e r g y \\ U & = & P o t e n t i a l e n e r g y \end{array}$

Step 2: Given

$mass m =5.00g sides of the triangle = 30.0cm$

Step 3: (a) Potential energy of the system

As described in the question the particles are located at the corners of the triangle and this triangle have equal three sides that is equilateral triangle.

The length of sides is 0.30m, so the gravitational potential energy of the system will be, if triangle is ABC,

$U_{T o t a l} = U_{A B} + U_{B C} + U_{C A} = 3 U_{A B} U_{T o t a l} = 3 (- \frac{G m_{A} m_{B}}{r_{A B}}) U_{T o t a l} = 3 (- \frac{6.67 \times 10^{- 11} N - m^{2} {/Kg×5.00×10}^{- 3} {Kg×5.00×10}^{- 3} Kg}{0.300 m}) U_{T o t a l} = - 1.67 \times 10^{- 14} J$

So the Total potential energy of the system will be $U_{T o t a l} = - 1.67 \times 10^{- 14} J$ .

Step 4: (b) Motion of the particles

The net force of attraction felt by a particle will be at the midpoint of the other two points of the triangle. Each particle of the triangle is moving towards the center point of the triangle, so the all particles will collide with each other at the center of the triangle.

Find Study Materials for

Create Study Materials

Select your language

Physics For Scientists & Engineers

Answers without the blur.

Short Answer

Step by Step Solution

Step 1: Conservation of energy

Step 2: Given

Step 3: (a) Potential energy of the system

Step 4: (b) Motion of the particles

Most popular questions for Physics Textbooks

Want to see more solutions like these?

Recommended explanations on Physics Textbooks

Select your language

Physics For Scientists & Engineers

Answers without the blur.

Short Answer

Step by Step Solution

Step 1: Conservation of energy

Step 2: Given

Step 3: (a) Potential energy of the system

Step 4: (b) Motion of the particles

Most popular questions for Physics Textbooks

Want to see more solutions like these?

Recommended explanations on Physics Textbooks

Work Energy and Power

Radiation

Astrophysics

Physics of Motion

Scientific Method Physics

Fluids

Torque and Rotational Motion

Nuclear Physics

Fields in Physics

Measurements

Space Physics

Electricity

Physical Quantities and Units

Medical Physics

Electrostatics

Further Mechanics and Thermal Physics

Mechanics and Materials

Engineering Physics

Energy Physics

Force

Particle Model of Matter

Waves Physics

Magnetism

Modern Physics

Atoms and Radioactivity

Dynamics

Electricity and Magnetism

Conservation of Energy and Momentum

Fundamentals of Physics

Kinematics Physics

Circular Motion and Gravitation

Linear Momentum

Rotational Dynamics

Oscillations

Translational Dynamics

Geometrical and Physical Optics

Thermodynamics

Magnetism and Electromagnetic Induction

Electromagnetism

Electric Charge Field and Potential

Turning Points in Physics