• :00Days
  • :00Hours
  • :00Mins
  • 00Seconds
A new era for learning is coming soonSign up for free
Log In Start studying!

Select your language

Suggested languages for you:
Deutsch (DE)
Deutsch (UK)
Deutsch (US)

Americas

Europe

Answers without the blur. Sign up and see all textbooks for free! → Illustration

Q15P

Expert-verified
Physics Principles with Applications
Found in: Page 230
Physics Principles with Applications

Physics Principles with Applications

Book edition 7th
Author(s) Douglas C. Giancoli
Pages 978 pages
ISBN 978-0321625922

Answers without the blur.

Just sign up for free and you're in.

Register for Free I’ll do it later
Illustration

Short Answer

The force required to pull the cork out of the top of a wine bottle is in the range of 200 to 400 N. What range of force F is required to open a wine bottle with the bottle opener shown in Fig. 9–55?

The required range of force on the opener is 20 N to 50 N.

See the step by step solution

Step by Step Solution

TABLE OF CONTENTS :
TABLE OF CONTENTS

Step 1: Concepts

When a cork is opened, there is no cork rotation; the only cork moves upward. The cork does not rotate, and the net torque on the cork is zero due to the force on the opener and the pull force.

Step 2: Given data

The required force to open the cork is \({F_ \circ } = 200\;{\rm{N}}\;{\rm{to}}\;400\;{\rm{N}}\).

The force on the opener is F.

Step 3: Calculation

According to Newton’s third law, the reaction force on the cork is downward. Here, the pivot point is at the edge where the end of the opener is touched with the bottle.

The free-body diagram of the problem is shown below.

Now, the condition for no rotation of the torque is

\(\begin{array}{c}F \times \left( {70\;{\rm{mm}} + 9\;{\rm{mm}}} \right) - {F_ \circ } \times \left( {9\;{\rm{mm}}} \right) = 0\\F = \frac{9}{{79}}{F_ \circ }\end{array}\).

Now, substituting the value of \({F_ \circ }\) in the above equation,

\(\begin{array}{c}F = \frac{9}{{79}}\left( {200\;{\rm{N}}\;{\rm{to}}\;400\;{\rm{N}}} \right)\\F = 22.78\;{\rm{N}}\;{\rm{to}}\;45.57\;{\rm{N}}\\F \approx 20\;{\rm{N}}\;{\rm{to}}\;50\;{\rm{N}}\end{array}\).

Hence, the required range of force on the opener is 20 N to 50 N.

Most popular questions for Physics Textbooks

A 23.0-kg backpack is suspended midway between two trees by a light cord as in Fig. 9–51. A bear grabs the backpack and pulls vertically downward with a constant force, so that each section of cord makes an angle of 27° below the horizontal. Initially, without the bear pulling, the angle was 15°; the tension in the cord with the bear pulling is double what it was when he was not. Calculate the force the bear is exerting on the backpack.

When you apply the torque equation \(\sum {\tau = 0} \) to an object in equilibrium, the axis about which the torques are calculated

(a) must be located at a pivot.

(b) must be located at the object’s center of gravity.

(c) should be located at the edge of the object.

(d) can be located anywhere.

A 2.0-m-high box with a 1.0-m-square base is moved across a rough floor as in Fig. 9–89. The uniform box weighs 250 N and has a coefficient of static friction with the floor of 0.60. What minimum force must be exerted on the box to make it slide? What is the maximum height h above the floor that this force can be applied without tipping the box over? Note that as the box tips, the normal force and the friction force will act at the lowest corner.

You can find the center of gravity of a meter stick by resting it horizontally on your two index fingers, and then slowly drawing your fingers together. First the meter stick will slip on one finger, and then on the other, but eventually the fingers meet at the CG. Why does this work?

A parking garage is designed for two levels of cars. To make more money, the owner decides to double the size of the garage in each dimension (length, width, and the number of levels). For the support columns to hold up four floors instead of two, how should he change the columns' diameter?

(a) Double the area of the columns by increasing their diameters by a factor of 2

(b) Double the area of the columns by increasing their diameters by a factor of \(\sqrt 2 \)

(c) Quadruple the area of the columns by increasing their diameters by a factor of 2

(d) Increase the area of the columns by a factor of 8 by increasing their diameters by a factor of \(2\sqrt 2 \)

(e) He doesn't need to increase the diameter of the columns
Icon

Want to see more solutions like these?

Sign up for free to discover our expert answers
Get Started - It’s free

Recommended explanations on Physics Textbooks

Work Energy and Power

Read explanation

Radiation

Read explanation

Astrophysics

Read explanation

Physics of Motion

Read explanation

Scientific Method Physics

Read explanation

Famous Physicists

Read explanation

Fluids

Read explanation

Torque and Rotational Motion

Read explanation

Nuclear Physics

Read explanation

Fields in Physics

Read explanation

Measurements

Read explanation

Space Physics

Read explanation

Electricity

Read explanation

Physical Quantities and Units

Read explanation

Medical Physics

Read explanation

Electrostatics

Read explanation

Further Mechanics and Thermal Physics

Read explanation

Mechanics and Materials

Read explanation

Engineering Physics

Read explanation

Energy Physics

Read explanation

Force

Read explanation

Particle Model of Matter

Read explanation

Waves Physics

Read explanation

Magnetism

Read explanation

Modern Physics

Read explanation

Atoms and Radioactivity

Read explanation

Dynamics

Read explanation

Electricity and Magnetism

Read explanation

Conservation of Energy and Momentum

Read explanation

Fundamentals of Physics

Read explanation

Kinematics Physics

Read explanation

Circular Motion and Gravitation

Read explanation

Linear Momentum

Read explanation

Rotational Dynamics

Read explanation

Oscillations

Read explanation

Translational Dynamics

Read explanation

Geometrical and Physical Optics

Read explanation

Thermodynamics

Read explanation

Magnetism and Electromagnetic Induction

Read explanation

Electromagnetism

Read explanation

Electric Charge Field and Potential

Read explanation

Turning Points in Physics

Read explanation

94% of StudySmarter users get better grades.

Sign up for free
94% of StudySmarter users get better grades.