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15-1Q
Expert-verifiedIn an isothermal process, 3700 J of work is done by an ideal gas. Is this enough information to tell how much heat has been added to the system? If so, how much? If not, why not?
The heat added to the system is 3700 J.
By the first law of thermodynamics, \(\Delta U = Q - W\).
For the isothermal process, change in internal energy, \({\bf{\Delta }}U = {\rm{0}}\).
For the isothermal process,
\(\begin{aligned}{c}0 = Q - W\\Q = W.\end{aligned}\)
In the isothermal process, the work done equals the heat supplied to the system.
Hence, the heat added to the system is 3700 J.
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