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10

Expert-verifiedFound in: Page 28

Book edition
14th edition

Author(s)
Hugh D. Young, Roger A. Freedman

Pages
1596 pages

ISBN
9780321973610

**The following conversions occur frequently in physics and are very useful. (a) Use 1 mi = 5280 ft and 1 h = 3600 s to convert 60 mph to units of ft/s. (b) The acceleration of a freely falling object is 32 ft/s ^{2}. Use 1 ft = 30.48 cm to express this acceleration in units of m/s^{2}. (c) The density of water is 1.0 g/cm^{3}. Convert this density to units of kg/m^{3}.**

(a) The velocity in ft/s is 88 ft/s.

(b) The acceleration in m/s^{2} is 18.3 m/s^{2}.

(c) The density in kg/m^{3} is 1000 kg/m^{3}.

Part (a)

The conversion in ft/s is shown below,

$60mph=60\frac{mi}{h}\times \frac{5280ft}{1mile}\times \frac{1h}{3600s}\phantom{\rule{0ex}{0ex}}60mph=88ft/s$

Thus, the value in ft/s is 88 ft/s.

Part (b)

The conversion in m/s^{2} is shown below,

$32ft/{s}^{2}=60\frac{ft}{h}\times \frac{30.48cm}{1ft}\times \frac{1m}{100cm}\phantom{\rule{0ex}{0ex}}32ft/{s}^{2}=18.3m/{s}^{2}$

Thus, the value in m/s^{2} is 18.3 m/s^{2}

Part (c)

The conversion in kg/m^{3} is shown below,

$1g/c{m}^{3}=1\frac{g}{c{m}^{3}}\times {\left(\frac{100cm}{1m}\right)}^{3}\times \frac{1kg}{1000g}\phantom{\rule{0ex}{0ex}}1g/c{m}^{3}=1000kg/{m}^{3}$

Thus, the value of density in kg/m^{3} is 1000 kg/m^{3}.

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